| BreakABone |
03-05-2002 05:21 PM |
Quote:
Originally posted by ed328
That is the answer if y=PI*(16-x²).
But y=sqrt(16-x²) which does not equal PI*(16-x²).
What exactly are the conditions that you have to use your formula PI*integral of [R(x)]²dx? From the information you've given us, Xantar and I are correct.
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Yeah I realized where I made the mistake.. you are supposed to find the volume not the area.. oops... |
