Ok Any Math Wise Help

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Ok Any Math Wise Help

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03-05-2002, 11:37 AM

ed328

Baron

ed328 is offline

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Quote:

Originally posted by BreakABone
Well if anyone cares to work it out..

The answer is 128pi/3

That is the answer if y=PI*(16-x²).

But y=sqrt(16-x²) which does not equal PI*(16-x²).

What exactly are the conditions that you have to use your formula PI*integral of [R(x)]²dx? From the information you've given us, Xantar and I are correct.

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