Re: How do I solve this?
Ignoring the possibility that someone was born on Feb29...
P = (365)(364)(363)....(365 - n + 1)/(365)^n where n = 30.
P = .29368, which is actually the probability that no two people have the same birthday, so
1 - .29368 = .70632 => .71
So in a room with 30 people, chances are more likely than not that two people will have the same birthday. May seem counterintuitive but it's true.
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Last edited by Neo : 12-01-2005 at 12:37 AM.
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